Economy, asked by 8004875530, 2 months ago


sin25.sin45 + cos52 + cos48

Answers

Answered by Anonymous
16

\mathfrak{Question}

sin25.sin45 + cos52 + cos48

\mathfrak{Answer}

➪ sin 45°. sin 45° + cos 52° + cos 48°

➪ sin ( 90° - 45° ) . sin ( 90° - 45° ) + cos ( 90° - 38° ) + cos (90° - 42°)

➪ cos 45°. cos 45° + sin 38° + sin 42°

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{\tt{{\underline{\underline{formula \: used}}}}}

✔ cos ( 90° - A° ) = sin A

✔ sin ( 90° - A° ) = cos A

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Other formulas:-

✔ tan ( 90° - A° ) = cot A

✔ sec ( 90° - A° ) = cosec A

✔ cosec ( 90° - A° ) = sec A

✔ cot ( 90° - A° ) = tan A

Answered by pratham7777775
3

Answer:

conquer user aap Kon ho (oO)

Explanation:

mod toh nhi ho XD

sin25.sin45 + cos52 + cos48

\mathfrak{Answer}Answer

➪ sin 45°. sin 45° + cos 52° + cos 48°

➪ sin ( 90° - 45° ) . sin ( 90° - 45° ) + cos ( 90° - 38° ) + cos (90° - 42°)

➪ cos 45°. cos 45° + sin 38° + sin 42°

__________________________

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