Question

$sin3\alpha =sin2\alpha$

Answer 1

sin3x=sin2x
=>3x=arc sin(sin2x)
so, 3x= nπ +((-1)^n)2x
=>3x-((-1)^n)2x=nπ
=>x{3-2((-1)^n)}=nπ
=>x=nπ/{3-2((-1)^n)}
[PS: Here alpha = x]