Prove the following by paper cutting activity .
Write some of the algebraic identities.
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Prove the following by paper cutting activity .
Answer:-
Objectives:-
- To verify the identity (a + b)2 = a2 + 2ab + b2 by paper cutting and pasting.
Prerequisite Knowledge :-
- Area of a square = (side)².
- Area of a rectangle = l x b.
Materials Required :-
A sheet of white paper, three sheets of glazed paper (different colours), a pair of scissors, gluestick and a geometry box.
Procedure :-
- Take distinct values of a and b, say a = 4 units, b = 2 units
- Cut a square of side a (say 4 units) on a glazed paper (blue).
- Cut a square of side b (say 2 units) on glazed paper (pink).
- Now, cut two rectangles of length a (4 units) and breadth b (2 units) from third glazed paper (red).
- Draw a square PQRS of (a+ b) = (4 + 2), 6 units on white paper sheet as shown in fig. (i).
- Paste the squares I and II and two rectangles III and IV on the same white squared paper. Arrange all the pieces on the white square sheet in such a way that they form a square ABCD fig. (ii)
Observation :-
- Area of the square PQRS on the white sheet paper.
- (a+b)² = (4+2)² = 6 x 6 = 36 sq. units ……….(i)
- Area of two coloured squares I and II
- Area of Ist square = a² = 4² = 16 sq.units
- Area of IInd square = b² = 2² = 4 sq.units
- Area of two coloured rectangles III and IV = 2(a x b) = 2(4 x 2) = 16 sq. units
- Now, total area of four quadrilaterals (calculated)
- = a² + b² + 2(ab)
- = 16+4+16
- = 36 sq. units ……….(ii)
- Area of square ABCD = Total area of four quadrilaterals = 36 sq. units
Equating (i) and (ii):-
- Area of square PQRS = Area of square ABCD i.e., (a+b)2 = a2 + b2 + 2ab
Result :-
- Algebraic identity (a+b)² = a²+ 2ab + b² is verified.
Learning Outcome:-
- The identity (a+b)2 = a2 + 2ab + b2 is verified by cutting and pasting of paper. This identity can be verified geometrically by taking other values of a and b.
There are three attachments for question 1.
Write some of the algebraic identities.
*Answer:-
Identity I:
(a + b)² = a² + 2ab + b²
Identity II:
- (a – b)² = a² – 2ab + b²
Identity III:
- a² – b²= (a + b)(a – b)
Identity IV:
- (x + a)(x + b) = x² + (a + b) x + ab
Identity V:
- (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
Identity VI:
- (a + b)³ = a³ + b³ + 3ab (a + b)
Identity VII:
- (a – b)³ = a³ – b³ – 3ab (a – b)
Identity VIII:
- a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c2 – ab – bc – ca)
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