Question

$\small{hey}$ ___________________Audible frequencies have a range 40hz to 30000hz. express this range in terms in (a) time period, (b) wavelength in air and (c) angular frequency. Given velocity in air is 350ms^-1
___________
$\bold{don't\:spam!}$

Answer 1

For a sound wave,

Speed = Wavelength x Frequencyv = λ x ν

Speed of sound in air = 350 m/s (Given)

(i) For, ν= 40 Hz

λ1= v/ν = 350/40 =8.705 m

(ii) For, ν= 30000 Hz

λ2= v/ν = 350/30000 = 85.7142857142 m

Answer 2

$\huge\bold{Answer}$

$<b><h><u>QUESTION$>>Audible frequencies have a range 40hz to 30000hz.

a.$\bold{time\: period}$

let, 40hz be f1, while 30,000hz be f2, hence,

f = f2 - f1

= 30,000-40

= 29,960 hz

hence the given frequency will be 29,690hz.

then we know that time period==>

T =$\frac{1}{f}$

T= $\frac{1}{29,960}$

T= 0.0000333$s^{-1}$

T = $3.33\times 10^{-5}\times s^{-1}$

b.wavelength

we have ,,

velocity of sound in air v = 350$m\times s^{-1}$

and

frequency, f = 29,600hz

hence,

Wavelength , V(commonly as lamda)= $\frac{v}{f}$

V = $\frac{350}{29,960}$

V = 0.0116m

V = $1.16\times 10^{-2}$

c.angular frequency. Given velocity in air is 350ms^-1

we have,

angular frequency (or) angular speed = 2πf

where f is the frequency..

hence,

angular frequency(omega,as )w = $2\times 3.14\times 29960$

= 1,88,148.8 rad hz

= 1,88,148.8 $rad\times s$>>

\\\\\be brainlyyy...