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Answered by
8
Hey friend ✋! here is your answer
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✅To solve - 3x^2+2x-1
✔️By factorization method
✅3x^2+3x-x-1
✔️Taking common
✅3x(x+1)-1(x+1)
✔️(3x-1)(x+1)=0
✔️3x-1=0 &x+1=0
✅x=1/3 & x=-1
___________________
⭐️Hope it helps you ⭐️
___________________________
✅To solve - 3x^2+2x-1
✔️By factorization method
✅3x^2+3x-x-1
✔️Taking common
✅3x(x+1)-1(x+1)
✔️(3x-1)(x+1)=0
✔️3x-1=0 &x+1=0
✅x=1/3 & x=-1
___________________
⭐️Hope it helps you ⭐️
Answered by
4
Hey Raju !!!
Solution :-
3x² + 2x - 1 = 0
3x² + 3 x - x - 1 [ spliting term ]
3x ( x + 1 ) - 1 ( x + 1 )
(3x - 1 ) ( x + 1 ) [ taking common ]
hence, 3x - 1 = 0
x = 1/3
and , x + 1 = 0
x = - 1
Here roots are - 1 and 1/3
_____________________
Hope it helps you !!!
@Rajukumar111 :-D
Solution :-
3x² + 2x - 1 = 0
3x² + 3 x - x - 1 [ spliting term ]
3x ( x + 1 ) - 1 ( x + 1 )
(3x - 1 ) ( x + 1 ) [ taking common ]
hence, 3x - 1 = 0
x = 1/3
and , x + 1 = 0
x = - 1
Here roots are - 1 and 1/3
_____________________
Hope it helps you !!!
@Rajukumar111 :-D
Anonymous:
lol
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