Question

$Solve\ for\ x:\\\\ (1-\tan x) (1+\tan x) \sec^2 x + 2^ {\tan^2 x} = 0$

Answer 1

Step-by-step explanation:

(1-tanx) (1+tanx)sec²x + 2^tan²x = 0

=> (1-tan²x) (1+tan²x) + 2^tan²x) = 0

=> 1-tan^4x + 2^tan²x =0

=> tan^4x - 2tan²x +1-2 = 0

=> (tan²x - 1)² -2 =0

=> (tan²x - 1)² = (√2)²

=> tan²x - 1 = √2

=> tan²x = √2 + 1

=> tanx =√(√2 + 1)

=> tanx = √2.414

=> x = tan-¹(2.414)

=> x = 67 degree

Answer 2

Answer:

PLEASE MARK BRAINLIEST

PLEASE FOLLOW ME