Math, asked by gunjansingh963, 9 months ago


solve \: for \: x \\  \sqrt{2x + 9}  + x = 13

Answers

Answered by dharun1
1

Answer:

The above given equation can be also written as

 \sqrt{2x + 9}  = 13 - x

When squared on both sides we get

 { (\sqrt{2 + 9} })^{2}  =  {(13 - x)}^{2}

when further solving

2x + 9 = 169 +  {x}^{2}   - 26x \\  \\  {x}^{2}  - 26x - 2x + 169 - 9  = 0\\  \\  {x}^{2}  - 28x + 160 = 0 \\  \\  {x}^{2}  - 20x - 8x  + 160 = 0 \\  \\ (x - 20)(x - 8) = 0 \\  \\ x = 20 \: or \: x = 8

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