Question

$solve \: for \: x \\ \sqrt{2x + 9} + x = 13$
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Answer 1

Answer:

The above given equation can be also written as

$\sqrt{2x + 9} = 13 - x$

When squared on both sides we get

${ (\sqrt{2 + 9} })^{2} = {(13 - x)}^{2}$

when further solving

$2x + 9 = 169 + {x}^{2} - 26x \\ \\ {x}^{2} - 26x - 2x + 169 - 9 = 0\\ \\ {x}^{2} - 28x + 160 = 0 \\ \\ {x}^{2} - 20x - 8x + 160 = 0 \\ \\ (x - 20)(x - 8) = 0 \\ \\ x = 20 \: or \: x = 8$