Question

$solve \: \frac{ x - 2}{4} + \frac{1}{3} = x - \frac{2x - 1}{3}$
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Answer 1

Answer:

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Answer 2

$\tt\frac{x - 2}{4} + \frac{1}{3} = x - \frac{2x - 1}{3}$

$\tt \: taking \: \: \: lcm$

$\tt \frac{3x - 6 + 4}{12} = \frac{3x - 2x - 1}{3}$

$\tt \frac{3x - 2}{12} = \frac{x - 1}{3}$

$\tt \: by \: cross \: multiplication$

$\tt \: 3(3x - 2) = 12(x - 1)$

$\tt \: 9x - 6 = 12x - 12$

$\tt9x - 12x = - 12 - 6$

$\tt - 3x = - 18$

$\tt \: x = \frac{\cancel{ - }18}{\cancel{ - }3}$

$\tt \: x \: = 6$

$\rm{\dashrightarrow .°.~Value~of~x~=~6}$