Question

$solve \: it\\ \\ 2 \sin^{ - 1} x = \cos^{ - 1} x \\ \\ find \: the \: value \: of \: x$

Chapter: Inverse Trigonometry

Answer: 1/2

Please don't give useless answer. It's a Request.

PLEASE SOLVE IT

Answer 1

............................ok

Answer 2

$The \: \: answer \: \: is \: \: given \: \: below \\ \\ Now, \: \: 2 {sin}^{ - 1} x = {cos}^{ - 1} x \\ \\ Or, \: \: 2 {sin}^{ - 1} x = \frac{\pi}{2} - {sin}^{ - 1} x \\ \\ (Since, \: \: {sin}^{ - 1} x + {cos}^{ - 1} x = \frac{\pi}{2} ) \\ \\ Or ,\: \: 3 {sin}^{ - 1} x = \frac{\pi}{2} \\ \\ Or, \: \: {sin}^{ - 1} x = \frac{\pi}{6} \\ \\ Or, \: \: x = sin \frac{\pi}{6} \\ \\ So ,\: \:x = \frac{1}{2} \\ \\ Thank \: \: you \: \: for \: \: the \: \: question.$