Question

$solve \: the \: following \: equation \: for \: x \\ \ \\ {4x}^{2} + 4bx \: - { {a}^{2} - {b}^{2} } = 0$
if u know only pls answer it


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Answer 1

Step-by-step explanation:

Nandu, here is your answer

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Answer 2

Answer:

your answer is here nandu.....

hope english exam, went smoothly?!

4x²+4bx-(a²-b²)

4x²+4bx-a²+b²

2x² + 2(2x)b +b²-a²=0

it is the form, a²+b²+2ab

then, in short (a+b)²

(2x+b)²-a²=0.......[a²-b²=(a+b)(a-b)]

(2x+b+a)(2x+b-a)=0

now by splitting,

2x+b+a=0. ;. 2x+b-a=0

then,

2x= -b-a. ;. 2x= a-b

x= -b-a/2. ;. x= a-b/2

hope this will help you..nandu...