Question

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Answer 1

Answer:

let intial force be F

When brought in contact they get equal charges

i.e 3q/4

Explanation:

New force be F¹=9/8F

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Answer 2

Find the force between the charges  q and q/2, if they brought in contact to each other and then brought away at their initial position.

Answer:

9/8 of the initial force

Explanation:

Let, initially, the force be F and distance  between them be r.

F = k q(q/2) / r²   = kq²/2r²

When they are brought in contact, charge must have distributed equally over their surface.

Charge on each sphere = average charge

                                    = (q + q/2)/2

                                    = 3q/4

Now,

Force = k (3q/4)(3q/4) /r²

          = (9/8)  [ kq²/2r² ]

          = 9/8  [F]

Force is 9/8 of the initial force.