Math, asked by doofuzz, 8 months ago

Solve\:using\:\log \:_a\left(m\right)=\frac{\log \:_b\left(m\right)}{\log \:_b\left(a\right)} What\:is\:\log \:_3\left(4\right)\cdot \:\log \:_4\left(5\right)\cdot \:\log \:_5\left(6\right)\cdot \:..............\cdot \:\log \:_{80}\left(81\right)\:? ?

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Answered by Anonymous
1

Answer:

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I have answered

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