Question

$solve \: {x }^ { 2} + 8 = 0$
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Answer 1

Step-by-step explanation:

Hi

X² + 8 = 0

X² = -8

X = √-8

X = √(-2) × (-2) × (-2)

X = 2√(-2)

Hence,

The value of x is 2underroot-2

Answer 2

Answer:

ANSWER :)

$x {}^{2} + 8 = 0 \\ x {}^{2} = - 8 \\ x = \sqrt{} - 8 \\ x = \sqrt{} ( - 2) \times ( - 2) \\ x = 2 \sqrt{} ( - 2) \\ hence \: x \: = 2 \sqrt{} ( - 2)$