Question

$solve \: x {}^{2} \: + 8x - 48 = 0 \: by \: completing \:$
$squar \: method$
​

Answer 1

Answer:

X = 8 OR -12

Step-by-step explanation:

x² + 8 x - 48 = 0

Sum = 8x

product = 48 x x² = 48x²

Factors of 8

1 x 48

2 x 12

3 x 16

4 x 12. ✓

6 x 8

12x x 4x= 48

12x - 4x = 8

therefore,

x² + (12x - 8x) + 48 = 0. [ 8x = 12x - 4x]

x² + 12x - 8x + 48 = 0

(simplify)

x ( x + 12) - 8 (x + 12) = 0

(x - 8) (x + 12) = 0

x - 8 = 0

x = 0 - 8

x = 8

or

x + 12 = 0

x = 0 - 12

x = -12

therefore x = 8 or x = -12!

HOPE THAT HELPS! <3