Question

$solve \\ {x}^{ \frac{2}{3} } - {x}^{ \frac{1}{3} } - 2 = 0$
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Answer 1

Step-by-step explanation:

$\sf {x}^{\frac {2}{3}} - {x}^{\frac{1}{3}} - 2 = 0$

$\sf Let\:y = {x}^{\frac {1}{3}}$

$\sf {y}^{2} - y - 2 = 0$

$\sf {y}^{2} - 2y + y - 2 = 0$

$\sf ( y - 2 )( y + 1 ) = 0$

$\sf y = 2$

$\sf {x}^{\frac {1}{3} } = 2$

$\sf \boxed {x = 8 }$

THANKS!!!