Math, asked by payalsharma81, 11 months ago


 \sqrt{1 +  \sin \infty ( \div ) 1 -  \sin( \infty ) }  =  \tan( \infty  +  \sec( \infty ) )

Answers

Answered by sandy1816
0

Step-by-step explanation:

√1+sin∞/1-sin∞

=√(1+sin∞)²/1-sin²∞

=√(1+sin∞)²/cos²∞

=1+sin∞/cos∞

=sec∞+tan∞

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