Question

$\sqrt{1 - sin2x}$
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Answer 1

Ans >> cosx- sinx


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Answer 2

Answer:

|sinx -cosx|

Step-by-step explanation:

$\sqrt{1-sin2x}$

1 can be written as $sin^{2} x+cos^{2} x$

sin2x can be written as 2sinx cosx

$\sqrt{sin^{2}x +cos^{2}x-2sinx cosx } \\\\\sqrt{(sinx-cosx)^2}$

opening the root,

we get

|sinx-cosx|=|cosx-sinx| =>whichever pleases you more

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