Question

$\sqrt{10 } locate \: on \: the \: number \: line$
​

Answer 1

$\large{ \blue{ \underline{ \sf{Question : - }}}}$

Represent √10 on the number line.

___________________________

$\large{ \green{ \underline{ \sf{Given : - }}}}$

• √10

$\large{ \purple{ \underline{ \sf{To \: find : - }}}}$

• Represent $( \sqrt{10})$ on the number line.

$\large{ \color{aqua}{ \underline{ \sf{Solution : - }}}}$

We can write,

$\sf \: ( \sqrt{10} )^{2} = (3)^{2} + (1) ^{2}$

So, we can Create a right angle triangle with these three values.

On number line, at 3, we can Create a perpendicular of 1 unit and then, from O, we can Create an art to top of perpendicular.

$\large{ \red{ \mathfrak{ \underline{ Answer : - }}}}$

Hence , point that are will cut on number line will be √10

____________________________

Answer 2

GIVEN -:

To Locate $\sf\sqrt{10 }$ on number line

We Can write $\sqrt{10 }$ as Follows

$\implies \sqrt{10} = \sqrt{9 + 1} \ \: \\ \implies \sqrt{10} = \sqrt{3^2 + 1^2}$

The construction steps are as follows:

1-: Take a line segment AO=3 unit on the x-axis. (consider 1 unit = 2 cm)

2. Draw a perpendicular on O and draw a line $\sf OC=1 unit$

3. Now join AC with $\sqrt{10 }$

4. Take A as center and AC as radius, draw an arc which cuts the x-axis at point E.

5. The line segment AC in the below diagram represents $\rm\sqrt{10 }$

_________________________