Question

$\sqrt{10 + \sqrt{25 + \sqrt{121 = } } }$
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Answer 1

The final answer is 4

Step-by-step explanation:

$\ Given \ value:\\\\\sqrt{10+\sqrt{25+\sqrt{121}}}\\\\\ Solution:\\\\\sqrt{10+\sqrt{25+\sqrt{121}}}\\\\\rightarrow \sqrt{10+\sqrt{25+\sqrt{(11)^2}}}\\\\\rightarrow \sqrt{10+\sqrt{25+11}}}\\\\\rightarrow \sqrt{10+\sqrt{36}}}\\\\\rightarrow \sqrt{10+\sqrt{(6)^2}}}\\\\\rightarrow \sqrt{10+6}\\\\\rightarrow \sqrt{16}\\\\\rightarrow \sqrt{4^2}\\\\\rightarrow 4$

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