Question

$\sqrt{1191.16 + 70 \sqrt{129.96} }$

Answer 1

solution:

let $\sqrt{1191.16+70 \sqrt{129.96} }=x$,
then,
[tex] x^{2} =1191.16+70 \sqrt{129.96} [/tex]
[tex]x^2=(1191.16+70(11.4)) [/tex]
[tex]x^2=(1196.16+798) [/tex]
$x^2=(1989.16)$
∴$x=44.6$

∴$\sqrt{1191.16+70 \sqrt{129.96} } = 46.4$
             Hope it Helps

Answer 2

Step-by-step explanation:

let \sqrt{1191.16+70 \sqrt{129.96} }=x

1191.16+70

129.96

=x ,

then,

x^{2} =1191.16+70 \sqrt{129.96}x

2

=1191.16+70

129.96

x^2=(1191.16+70(11.4))x

2

=(1191.16+70(11.4))

x^2=(1196.16+798)x

2

=(1191.16+798)

x^2=(1989.16)x

2

=(1989.16)

∴x=44.6

∴\sqrt{1191.16+70 \sqrt{129.96} } = 44.6

HOPE THIS HELPS YOU