Question

$\sqrt{13 - x \sqrt{10} } = \sqrt{8} + \sqrt{5} \\ then \: find \: value \: of \: x$
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Answer 1

$\sqrt{13 - x \sqrt{10} } = \sqrt{8 } + \sqrt{5}$

13-x√10 = (√8+√5)²

13-x√10 = 8+5+2√40

13-x√10 = 13+4√10

-x√10 = 4√10

-x = 4√10/√10

-x = 4

So,

x = -4

Cheers!