Question

$\sqrt{1443.98} \div 18.98 + 328.1 = a \times 22.01$
find the value of a​

Answer 1

Answer:

14.9978

Step-by-step explanation:

Answer 2

Answer:

Required value of a is 14.923.

Step-by-step explanation:

Given,

$\sqrt{1443.98} \div 18.98 + 328.1 = a \times 22.01$

We can solve this problem by BODMAS rule,

By BODMAS rule,

Bracket - Of - Division - Multiplication - Addition - Subtraction

$\sqrt{ \frac{1443.98}{100} } \div 18.98 + 328.1 = a \times 22.01 \\ 3.8 \div 18.98 + 328.1 = a \times 22 \\ \frac{3.8}{18.98} + 328.1 = a \times 22 \\ 0.20010 + 328.1 = a \times 22 \\ 22a = 328.3001 \\ a = \frac{328.3001}{22} \\ a = 14.923$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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