Question

$\sqrt{2} cosx+1=0$

Answer 1

Answer:

x = 135° and 225°

Step-by-step explanation:

$\sqrt{2} cosx+1=0$

$\sqrt{2} cosx = -1$

$cosx = -1/ \sqrt{2}$

We know that cos 135° and cos 225° is $-1/ \sqrt{2}$

So,

x = 135° and 225°

HOPE IT HELPS!!!

Answer 2

Step-by-step explanation:

Plz refer to the attachment..........

Hope it helps u....