Math, asked by Ryanjdude01, 1 month ago

(\sqrt{2} -\sqrt{3})/\\\sqrt{2} +\sqrt{3}

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Answered by Anonymous
2

Answer:

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Answered by LaeeqAhmed
0

 \frac{ \sqrt{2}  -  \sqrt{3} }{ \sqrt{2}  +  \sqrt{3} }

 \implies  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2}  +  \sqrt{3} }  \times  \frac{ \sqrt{2}  -  \sqrt{3} }{ \sqrt{2} -  \sqrt{3}  }

\implies  \frac{ (\sqrt{2} -  \sqrt{3}  )^{2}  }{ (\sqrt{2})^{2}    -  (\sqrt{3})^{2}  }

\implies  \frac{ (\sqrt{2} -  \sqrt{3}  )^{2}  }{ 2    -  3  }

\implies  \frac{{2 + 3 - 2 \sqrt{6} }  }{ 2    -  3  }

\implies  \frac{{5- 2 \sqrt{6} }  }{  - 1  }

 \orange{\therefore  2 \sqrt{6} - 5 }

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