Math, asked by nisu51, 7 months ago


 \sqrt{2 +  \sqrt{6} }

Answers

Answered by jaidansari248
2

we \: know \: that \\  \sqrt{m + n}   \\ =  \sqrt{ \frac{m  +   \sqrt{ {m}^{2}   -   {n}^{2} } }{2} }  +  \sqrt{ \frac{m - \sqrt{ {m}^{2} -  {n}^{2}  } }{2} }  \\ so \\  \sqrt{2 +  \sqrt{6} }  \\ m = 2 \:  \: \:  \:  \:  \:  \:  n =  \sqrt{6}  \\  =  \sqrt{ \frac{2  +  \sqrt{2 {}^{2}  -  \sqrt{6} {}^{2}  } }{2} }  +  \sqrt{ \frac{2 -  \sqrt{2 {}^{2} -  { \sqrt{6} }^{2}  } }{2} }  \\  =  \sqrt{ \frac{2 +  \sqrt{4 - 6} }{2} }  +  \sqrt{ \frac{2 -  \sqrt{4 - 6} }{2} }  \\  =  \sqrt{ \frac{2 +  \sqrt{2} i}{2} }  +  \sqrt{ \frac{2 -  \sqrt{2}i }{2} }


nisu51: thank u so much
jaidansari248: Its ok
Answered by amankp79
1

Step-by-step explanation:

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