Question

$\sqrt{2} {x}^{2} - 3x - 2 \sqrt{2}$
Solve this and find the value of x​

Answer 1

Step-by-step explanation:

$\sqrt{2} {x}^{2} - 3x - 2 \sqrt{2} \\ \\ \sqrt{2} {x}^{2} - 4x + x - 2 \sqrt{2} \\ \\ ( \sqrt{2} {x}^{2} - 4x) + (x - 2 \sqrt{2} ) \\ \\ \sqrt{2} x(x - 2 \sqrt{2} ) + 1(x - 2 \sqrt{2} ) \\ \\ ( \sqrt{2} x + 1)(x - 2 \sqrt{2} ) = 0\\ \\ \sqrt{2} x + 1 = 0 \: or \: x - 2 \sqrt{2} = 0 \\ \\ \sqrt{2} x = - 1 \: or \: x = 2 \sqrt{2} \\ \\ x = \frac{ - 1}{ \sqrt{2} } \: or \: x = 2 \sqrt{2}$