Question

$\sqrt{2} x {}^{2} - 3x + \sqrt{2} = 0$
by quadratic formula​

Answer 1

Answer:

${x}^{2} \sqrt{2} - 2x - x + \sqrt{2} = 0 \\ x \sqrt{2} (x - \sqrt{2} ) - 1(x - \sqrt{2} ) = 0 \\(x \sqrt{2} - 1)(x - \sqrt{2} ) = 0 \\ either (x \sqrt{2} - 1) = 0 \: \: or(x - \sqrt{2} ) = 0 \\ x = \frac{1}{ \sqrt{2} } \: \: or \: \: x = \sqrt{2}$