Question

$\sqrt{2}x {}^{2} + 3x + \sqrt{2}$
​

Answer 1

Answer:

√2x² +3x +√2

so factors are

√2x² +2x + x +√2

√2x(x+√2) + 1(x +√2)

(x+√2)(√2x+1)

x = -√2

x = -1/√2

Step-by-step explanation:

hope it helps

plz mark me as BRAINLIEST