Question

$\sqrt{2} {x}^2 + 3x + \sqrt{2} {?}$
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Answer 1

Step-by-step explanation:

$\sqrt{2} {x}^{2} + 3x + \sqrt{2} \\ = \sqrt{2} {x}^{2} + 2x + x + \sqrt{2} \\ = \sqrt{2} x(x + \sqrt{2} ) + 1(x + \sqrt{2} ) \\ = (x + 2)( \sqrt{2} x + 1)$