Math, asked by mohirevaibhavi, 3 months ago


  \sqrt{2} {x}^{2}  + 7 {x}^{2}  + 5 \sqrt{2}  = 0
 \sqrt{2}  {x}^{2}  +  \:  \:  \:  +  \:  \:  \:  + 5 \sqrt{2}  = 0
x( \:  \:  \: ) +  \sqrt{2} ( \:  \:  \: ) = 0
( \:  \:  \: )(x +  \sqrt{2} ) = 0
x =  \:  \:  \:  \:  \: or \: x =  -  \sqrt{2}
 \:  \:  \: and \:  -  \sqrt{2}  \: are \: roots \: of \: the \: equation

Answers

Answered by nariseamalavathi
0

Step-by-step explanation:

√2x²+7x+5√2=0

√2x²+2x+5x+5√2=0

√2x(x+√2)+5(x+√2)=0

(√2x+5)(x+√2)=0

x= -5/√2 ,-√2

Similar questions