Question

$\sqrt{2} x {}^{2} + 7x + 5 \sqrt{2 } = 0 \: factorisation \: method$

Answer 1

$\sqrt{2} x {}^{2} + 7x + 5 \sqrt{2 } = 0 \\ \sqrt{2} x {}^{2} + 2x + 5x + 5 \sqrt{2 } = 0 \\ \sqrt{2} x(x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0 \\ (\sqrt{2} x + 5)(x + \sqrt{2} ) = 0 \\ \\ \sqrt{2} x + 5 = 0 \\ x = \frac{ - 5}{ \sqrt{2} } \\ x = \frac{ - 5 \sqrt{2} }{2} \\ \\ x + \sqrt{2} = 0 \\ x = - \sqrt{2}$