Question

$\sqrt{2} {x }^{2} + 7x + 5 \sqrt{2 } = 0$
solve the quadratic equation by factorisation method


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Answer 1

Step-by-step explanation:

√2 x² +7x +5 √2 = 0

⇒ √2 x² + 5x + 2x + 5√2 = 0

 ⇒ √2x²  + 5x + √2*√2*x + 5√2=0

⇒ x(√2x + 5) + √2(√2x + 5) =0

⇒ (x+√2)(√2x+5) = 0

so answer =

x= - √2 or  x= - 5/√2

what is quadratic equation ?

• The word quadratic is derived from latin word  quadratus meaning square .
• x , y , z ....... are used to find unknown values in quadratic equations where a ≠0 .
• If x = 0 , then it is a linear equation.
• The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.
• It is a type of equation in which the highest degree is 2 .

Answer 2

Answer:

The value of x are -√2 and -5/√2.

Step-by-step explanation:

We can solve this question by factorisation method.

The full process is as follows:-

√2x² +7x+5√2=0

Now first we multiply √2*5√2=10

After Factorising 10 we get 2*5

So now the equation=

√2x²+5x+2x+5√2=0

Taking commons , we get:-

x(√2x+5)+√2(√2x+5)=0

=>(x+√2)(√2x +5)=0

Hence the value of x= -√2 or -5/√2.