![\sqrt{2}x^{2} + 7x + 5 \sqrt{2} = 0 \sqrt{2}x^{2} + 7x + 5 \sqrt{2} = 0](https://tex.z-dn.net/?f=+%5Csqrt%7B2%7Dx%5E%7B2%7D++%2B+7x+%2B+5+%5Csqrt%7B2%7D++%3D+0)
to solve this quadration by factorisation
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√2x²+7x+5√2 = 0
product = √2×5√2 =10
sum=7
numbers are 5 and 2
equatiom becomes
√2x²+2x+5x+5√2=0
√2x(x+√2) + 5(x+√2)
(√2x+5)(x+√2)
x= -5√2/2 , -√2
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