Math, asked by 62626281jyoti, 21 days ago


( \sqrt{2m +  \sqrt{3n)} }  {?}^{2}
Using the standard formulae, expand of the following ​

Answers

Answered by pandaanupama643
1

Answer:

As, (a+b)² = a²+b²+2ab

= (√2m + √3n)²

= (√2m)² + (√3n)² + 2 × (√2m) × (√3n)

= 2m² + 3n² + 2√6mn.

I think this may help you.

Step-by-step explanation:

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