Math, asked by vibhanshu16, 1 year ago


 \sqrt{2x {}^{2} }  + 3x +  \sqrt{2}

Answers

Answered by avinashsingh48
3
according to your question we can solve it by the help of this rule ax square +ax+ a
here is your solution
route 2*route 2=2
( route 2x square +2x)+(1x+ route 2)
X(route 2+x)+1(X+ route 2)
(X+1)(route 2 + X)
I hope it helps you so please make me brainliest
Answered by LeeMinHo2
0
\sqrt{2x{}^{2} } + 3x +\sqrt{2}
\sqrt{2x{}^{2} } + 2x+x+\sqrt{2}
(√2x^2+2x)+(x+√2)
√2x(x+√2)+1(x+√2)
(√2x+1)(x+√2)
...... I hope it will help you

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