Question

$\sqrt{2x {}^{2} } + 7 + 5 \sqrt{2 = 0}$
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Answer 1

Answer

√2x^2 + 7x + 5√2 = 0

==> √2x^2 + 5x +2x + 5√2 = 0

==> √2x² + 5x + √2*√2*x + 5√2=0

==> x(√2x + 5) + √2(√2x + 5) =0

==> (x+√2)(√2x+5) = 0

That gives x= - √2 or x= - 5/√2

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