Question

$\sqrt{2x ^{2} } + 7x + 5 \sqrt{2} = 0$
By quadratic formula or Shridhar Acharya formula​

Answer 1

Answer:

-5√2/(7+√2)

Step-by-step explanation:

we can rewrite the given question as:

√2(x) + 7x = -5√2

so x= -5√2/(7+√2)