Question

$\sqrt{2x {}^{2} } + 7x + 5 \sqrt{2}$
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Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0 \\ \\ = > \sqrt{2} {x}^{2} + 2x + 5x + 5 \sqrt{2} = 0 \\ \\ = > \sqrt{2x} (x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0 \\ \\ \\ = > ( \sqrt{2} x + 5)(x + \sqrt{2} ) = 0 \\ \\ = > \sqrt{2} x + 5 = 0 \\ \\ \\ x = \frac{ - 5}{ { \sqrt{2} } } \\ \\ \\ = > x + \sqrt{2} = 0 \\ \\ x = - \sqrt{2}$

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