Question

$\sqrt{2x + 9 } \: + x = 13$
root of 2 X + 9 + X = 13 ​

Answer 1

$\sqrt{2x + 9} + x = 13$

Refer to Attachment

#9thGrader

Kindly Follow this kiddo

Answer 2

Answer:

$\sqrt{2x+9}+x=13\\=>\sqrt{2x+9}=13-x\\=>2x+9=(13-x)^{2}$ (squaring both sides)

$=>2x+9=13^{2}+x^{2}-2*13*x$       $(a+b)^{2}=a^{2}+b^{2}+2ab$

$=>2x+9=169+x^{2}-26x\\=>2x+26x=169+x^{2}-9\\=>28x=160+x^{2}\\=>28x-x^{2}=160\\=>x(28-x)=160\\=>28-x=\frac{160}{x}\\=>-x=\frac{160}{x}-28=\frac{160-28x}{x}\\=>-x^{2}=160-28x$

This was how far I could get mate. Tell me if you could crack this sum. I am very intrigued.