Question

$\sqrt[3]{125} \times \sqrt[3]{64} \div \sqrt[3]{125} - \sqrt[3]{64}$
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Answer 1

Answer:

ans :20

step by Step explanation :

1) cube root of 125 is 5

2) cube root of 64 is 4

3) 5*4/5-4 = 20

Answer 2

Answer:

solution:

$\implies\sqrt[3]{125} \times \sqrt[3]{64} \div \sqrt[3]{125} - \sqrt[3]{64}$

${ \implies {\sqrt[3]{5\times5\times5}\times \sqrt[3]{4\times4\times4} \div \sqrt[3]{5\times5\times5} - \sqrt[3]{4 \times 4 \times 4} }}$

$= (5 \times 4) \div (5 - 4)$

$= 20$