Question

$\sqrt[3]{1728} \div \sqrt[5]{4096} =$
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Answer 1

Answer:

$\sqrt[3]{1728}\div \sqrt[5]{4096}\\= \frac{\sqrt[3]{1728}}{\sqrt[5]{4096}}\\\\= \frac{2^2\cdot \:3}{2^2\sqrt[5]{2^2}}= \frac{3}{\sqrt[5]{2^2}}\\\\= \frac{3}{\sqrt[5]{4}} = \frac{3\cdot \:2^{\frac{3}{5}}}{2}\\\\= \frac{3}{2^{1-\frac{3}{5}}} = \frac{3}{2^{\frac{2}{5}}}$

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