Question

$\sqrt[3]{2.197} + \sqrt{0.0049}$
​

Answer 1

Answer:

If 'V' is the 'Volume of a Cuboid' of Dimensions a, b c and 'S' is its 'Surface Area' then Prove that \boxed {\frac{1}{V} = \frac{2}{S} \Big (\frac{1}{a} + \frac{1}{b} + \frac{1}{c} \Big )}

V

1

=

S

2

(

a

1

+

b

1

+

c

1

)

-

NOTE :- \mathfrak {\red {Spams\: will\: be\: Deleted\: on\: the \: Spot :) }}SpamswillbeDeletedontheSpot:)

\mathfrak {\bold {Topic} - Class\: 9 - Volume\: and\: Surface\: Areas\: of\: Solids}Topic−Class9−VolumeandSurfaceAreasofSolids

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