Math, asked by devidas41kadam, 6 months ago


 \sqrt[3]{ - 2 {}^{6} }  + 6 {}^{2 {}^{0} }

Answers

Answered by ksaqlain2559
0

Answer:

hlo im also new

Step-by-step explanation:

Answered by kedarsanika1111
0

Step-by-step explanation:

 \sqrt[3]{ { - 2}^{6} }  +  {6}^{ {2}^{0} }

Calculate the cube root

 { - 2}^{2}  + 6 {}^{ {2}^{0} }

Any non-zero expression raised to the power of 0 equals 1

 { - 2}^{2}  +  {6}^{1}

Evaluate the power

 - 4 +  {6}^{1}

Any expression raised to the power of 1 equals itself

   - 4 + 6

Calculate the sum

 = 2

Here is your answer...

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