Question

$\sqrt{3 - 2 \sqrt{2} }$
Simply it ​

Answer 1

Answer:

$= > \sqrt{2} - 1$

Explanation:

$Here =>\sqrt{3 - 2 \sqrt{2} }$

$Let's \: expand \: = > \sqrt{2 + 1 - 2 \sqrt{2} }$

$= \sqrt{( \sqrt{2} ) {}^{2} + (1) {}^{2} - 2 \times 1 \times \sqrt{2} }$

$We \: all \: know \: that \\ a {}^{2} - 2ab + b {}^{2} = (a - b) {}^{2}$

$Therefore \: \sqrt{3 - 2 \sqrt{2} } \\ = \sqrt{(\sqrt{2} - 1) {}^{2} }$

$= (( \sqrt{2} - 1) {}^{2} ){}^{ \frac{1}{2} }$

$= ( \sqrt{2} - 1) {}^{2 \times \frac{1}{2} }$

$that \: is \: = > \sqrt{2} - 1$

Hope this works!!! <(￣︶￣)>