Question

$\sqrt{3 + 2 \sqrt{2} }$
Simplyfy

Answer 1

$\sqrt {3+2 \sqrt {2}}\\ = \sqrt { 1+2 +2 \sqrt{1 \times 2}} \\ =\sqrt {( \sqrt{1})^{2} + (\sqrt {2})^{2} + 2\sqrt {1 \times 2}}\\ = \sqrt {1} + \sqrt {2}$