Math, asked by nuhaaftab040206, 1 month ago


 \sqrt[3]{2196} =
find the cube root

Answers

Answered by xxMahiraxx
1

Answer:

Answer:The principal, real, root of:

Answer:The principal, real, root of:2196−−−−√3

Answer:The principal, real, root of:2196−−−−√3=12.9980273

Answer:The principal, real, root of:2196−−−−√3=12.9980273All roots:

Answer:The principal, real, root of:2196−−−−√3=12.9980273All roots:12.9980273

Answer:The principal, real, root of:2196−−−−√3=12.9980273All roots:12.9980273−6.49901366+11.2566219i

Answer:The principal, real, root of:2196−−−−√3=12.9980273All roots:12.9980273−6.49901366+11.2566219i−6.49901366−11.2566219i

Answer:The principal, real, root of:2196−−−−√3=12.9980273All roots:12.9980273−6.49901366+11.2566219i−6.49901366−11.2566219i2196 is not a perfect cube

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