Question

$\sqrt[3]{35.285 {}^{2} \ + 23.45 {}^{3} }$
solve by log table​

Answer 1

Step-by-step explanation:

How do I solve this equation using log tables?

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We will solve it partwise.

First of all let us suppose,

(35.285)^2 = a

Taking log of both sides

2 log (35.285) = log a

3.0952 = log a

Now taking antilog

antilog (3.0952) = a

=> 1245.09 = a ........(i)

Similarly let us suppose

(23..45)^3 = b

Taking log we get

4.1104 = log b

Now take antilog

12895.3 = b .........(ii)

Adding (i) and (ii)

We get value of expression inside cube root.

Now let us suppose (a+b)^1/3 = x

=> (14140.39)^1/3 = x

Taking log

1/3 log (14140.39) = log x

=> 1.3835 = log x

Now take antilog to get value of x.

X = 24.182