Question

$\sqrt[3]{4} \sqrt{3} \sqrt[4]{6}$
ascending order​

Answer 1

Answer:

this is the answer I guessed:

Step-by-step explanation:

⁴√6<³√4<√3

Answer 2

Answer:

| Arrange them in ascending order \(\sqrt[4]{6},\sqrt[3]{3}\) and \(\sqrt[3]{4}\)

A. <span class="math-tex">\(\sqrt[3]{3} &lt; \sqrt[4]{6} &gt; \sqrt[3]{4}\)</span>

B. <span class="math-tex">\(\sqrt[3]{3} &gt; \sqrt[4]{6} &gt; \sqrt[3]{4}\)</span>

C. <p><span class="math-tex">\(\sqrt[3]{3} &lt; \sqrt[3]{4} &gt; \sqrt[4]{6}\)</span></p>