Math, asked by Telex22, 1 month ago


( \sqrt{3}  -  \sqrt{2} )( \sqrt{3}  +  \sqrt{2} ) =  \: kya \: hai

Answers

Answered by prachidhruw
67

Answer:

Answer is 1

Step-by-step explanation:

( a + b ) ( a - b ) = -

so,

(3 - 2) ( 3 + 2)

(3)² - (2)²

3 - 2

1

hope this answer helps you dear...take care!

Answered by telex
497

Appropriate Question :-

Simplify \rm{( \sqrt{3} - \sqrt{2} )( \sqrt{3} + \sqrt{2} )}

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Solution :-

Given Information :-

  • Expression\bf{( \sqrt{3} - \sqrt{2} )( \sqrt{3} + \sqrt{2} )}

To Find :-

  • The simplification of the expression

Concept :-

  • Squares & Square Roots

Formula Used :-

  •  \boxed{\boxed{\bf(  \red{{a}^{2} } +  \green{ {b}^{2}} ) = \blue{ (a + b)(a - b)}}}

Explanation :-

  • Simply substitute the given values in the formula mentioned above and solve the expression. Simple and minute calculations will be done, the resultant will be the answer to our question. So, now, let's proceed towards our calculation.

Calculation :-

Using the Formula,  \boxed{\boxed{\rm (  \red{{a}^{2} } +  \green{ {b}^{2}} ) = \blue{ (a + b)(a - b)}}}

Substituting the values given in the formula, We get,

 \sf: \implies  \purple{( \sqrt{3} -  \sqrt{2}  )( \sqrt{3}  +  \sqrt{2} )}

When these two brackets are multiplied with each other, We get,

 \sf:  \implies   \purple{(\sqrt{3}  \times  \sqrt{3} ) -  (\sqrt{2}  \times  \sqrt{2} )}

We can also write this as,

 \sf:  \implies  \purple{ {( \sqrt{3} )}^{2} }  \purple {-  { (\sqrt{2}) }^{2}  }

We know that, When any square root is raised to the power 2, then the roots and power is cancelled.

 \sf:  \implies  \pink{3 - 2}

Subtracting, We get,

 \bf:  {\implies \boxed{ \red{ \bf1}}}

 \bf \therefore \blue{ ( \sqrt{3} - \sqrt{2} )( \sqrt{3} + \sqrt{2} ) }=   \boxed{\boxed{ \bf \red1}}

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Final Answer :-

  • \orange{( \sqrt{3} - \sqrt{2} )( \sqrt{3} + \sqrt{2} ) }=  \boxed{\boxed{\bf\red1}}

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