Math, asked by gunnugunnumehra, 3 months ago


( \sqrt{3 }  -  \sqrt{2} )( \sqrt{3}  -  \sqrt{2} )

Answers

Answered by THEmultipleTHANKER
11

( \sqrt{3 } - \sqrt{2} )( \sqrt{3} - \sqrt{2} ) \\   ( \sqrt{3 } - \sqrt{2} )^2 \\ \sqrt{3 }^2+\sqrt{2} -2(\sqrt{3 })(\sqrt{2}) \\ 3+2-2\sqrt{6} \\ 5-2\sqrt{6}

Answered by wwwuamuam
170

 \huge \purple{Question \ : }

( \sqrt{3}   -  \sqrt{2} )( \sqrt{3}  -  \sqrt{2} )

 \red{formula:}

(a - b)(a - b) =  {(a - b)}^{2}

 {(a - b)}^{2}  =  {a}^{2}  +  {b}^{2}  - 2ab

 \huge \pink{ \fbox{Answer:}}

(  \sqrt{3}  -  \sqrt{2} )( \sqrt{3}  -  \sqrt{2} )

 =  {( \sqrt{3} -  \sqrt{2})  }^{2}

 =  {( \sqrt{3} )}^{2}  + ( \sqrt{2} ) {}^{2}  - 2( \sqrt{3} )( \sqrt{2} )

 = 3 + 2  -  2( \sqrt{6} )

   \green{=  5 - 2 \sqrt{6} }

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